If a population proportion is believed to be 0.6, how many items must be sampled to ensure that the sampling distribution of ModifyingAbove p with caret will be approximately normal? Assume that the size of the population is Upper N equals 10 comma 000.

The answer is 5

Step-by-step explanation:

From the question given, we have to make reference to what we already know.

Recall that, for normality assumptions np and nq values need to be greater than or equal to 5.

Hence,

P = 0.6, where p = population proportion

q = 1 - p=

1 - 0.6 = 0.4

n = 13

thus,

np = 13 x 0.6 = 7.8 > 5

Therefore,

nq = 13 x 0.6 = 5.2 > 5

5

Step-by-step explanation:

To solve this we have to make reference to what we already know.

We already know that for normality assumptions np and nq values need to be greater than or equal to 5.

Hence, given;

P = 0.6

q = 1 - p = 1 - 0.6 = 0.4

n = 13

np = 13 * 0.6 = 7.8 > 5

nq = 13 * 0.6 = 5.2 > 5