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10 August, 11:46

Write an equation of a parabola that opens downward, has a vertex at the origin, and a focus at (0, - 1).

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  1. 10 August, 12:03
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    Y=a (x-h) ² + k, vertex (0,0)

    (h, k) vertex, h=0, k=0

    y=a (x-0) ²+0=ax

    y=ax²

    focus (h, k + 1/4*a) focus (0, - 1)

    k + 1/4 * a = - 1,

    0+1/4 a=-1

    1/4a=-1

    a=-4

    y = ax². y=-4x²
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