The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If 2.51% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the weight of the heaviest barbell that could be lifted a distance of 2.12 m?

F = 49,56 Kgs

Step-by-step explanation:

We Know that 113 calories = 4186 J

Joules (energy unit in MKS system meter, kilograms, second)

and 2,51 % of 4186 is 0,0251 * 4186 = 105.07 J

That the energy available

Work is W = F * d

where F is the force you have to apply and d is traveled distance

in this case F is the weight of the barbell

Then

F = W / d ⇒ F = 105.7 / 2.12 ⇒ F = 49,56 Kgs