Is the polynomial 3x2 (x2 + 2x + 1) completely factored? If not, factor it.

A. no; 3x2 (x + 1) (x + 2)

B. true

C. no; 3x2 (x + 1) (x - 1)

D. no; 3x2 (x + 1) 2

For this case we have the following polynomial:

3x2 (x2 + 2x + 1)

We observe that the polynomial is not completely factored.

The expression in parentheses can be factored.

We then have to rewrite:

3x2 ((x + 1) (x + 1))

3x ^ 2 (x + 1) ^ 2

Answer:

D. no; 3x2 (x + 1) 2