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Micheal Arias
Mathematics
13 February, 04:32
What must be added to 3x-7 to make x^24x-1
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Ean Haynes
13 February, 04:48
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You need to add: x2 + x+6
Explanation:
Let the unknown part be represented by A
Then we have: 3x-7+A = x2 + 4x-1
Subtract 3x from both sides
-7+A = x2 + 4x-3x-1
but 4x-3x is giving:
-7+A = x2 + x-1
Add 7 to both sides
A = x2 + x+6
So you need to add: x2 + x + 6
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