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13 February, 04:32

What must be added to 3x-7 to make x^24x-1

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  1. 13 February, 04:48
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    You need to add: x2 + x+6

    Explanation:

    Let the unknown part be represented by A

    Then we have: 3x-7+A = x2 + 4x-1

    Subtract 3x from both sides

    -7+A = x2 + 4x-3x-1

    but 4x-3x is giving:

    -7+A = x2 + x-1

    Add 7 to both sides

    A = x2 + x+6

    So you need to add: x2 + x + 6
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