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1 June, 11:34

two airplanes leave an airport at the same time and travel in opposite directions. one plane travels 70km/h slower than the other. if the two planes are 5472 km apart after 3 hours what is the rate of each plane

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  1. 1 June, 11:59
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    The speeds are 877 km/h and 947 km/h.

    Step-by-step explanation:

    The slower plane travels at x km/h. The faster plane travels at (x + 70) km/h. The speed of separation is the sum of the speeds, (2x + 70) km/h.

    They are 5472 km after 3 hours of travel.

    speed = distance/time

    2x + 70 = 5472/3

    2x + 70 = 1824

    2x = 1754

    x = 877

    The slower plane travels at 877 km/h.

    x + 70 = 877 + 70 = 947

    The faster plane travels at 947 km/h.
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