What are three consecutive odd integers whose product of the first and the third is for less than the square of the second

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Mathematics

12 January, 03:55

What are three consecutive odd integers whose product of the first and the third is for less than the square of the second

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Ezequiel Mckay · Answer 1

in steps

Step-by-step explanation:

Are you trying to prove any 3 positive consecutive odd integers whose product of the first and the third is four less than the square of the second?

3 positive consecutive odd integers: x-2, x, x+2

(x-2) (x+2) = x² - 4 ... correct

11, 13, 15 11 x 15 = 165 = 13² - 4