Find the vertex and zeros of the following function f (x) = x^2-6x-7

Try this solution:

Step-by-step explanation:

1) for zeros of the function: x²-6x-7=0; ⇒ x₁=7; x₂ = - 1.

2) for the vertex of the function: x₀ = - b/2a, where a; b; c - numbers from ax²+bx+c=0 (from x²-6x-7=0).

x₀=6/2=3;

y₀ = (4ac-b²) / 4a; ⇒ y₀ = - 16.

It means, the coordinates of the vertex are (3; -16).