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14 November, 08:21

In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find AC, if CD = 6 sqrt 2

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  1. 14 November, 08:31
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    AC = 12 units.

    Step-by-step explanation:

    Δ ACD is right-angled. (as CD ⊥ AB).

    cos 45° = CD / AC = 6√2 / AC

    AC = 6√2 / cos 45°

    AC = 6√2 / 1 / √2

    = 6√2 * √2

    = 6 * 2

    = 12 (answer)
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