What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y - 1?

P = 2x + 2y + 18

P = 2x + 2y + 14

P = x + y-9

P = x + y + 7

P=2x+2y+14

Step-by-step explanation:

Perimeter (P) of a rectangle = 2 (l+b)

where l is the length and b is the width of the rectangle.

Here, l = x+8

and, b = y-1

so, P = 2{ (x+8) + (y-1) }

= 2 (x+8+y-1)

= 2 (x+y+7)

=2x+2y+14