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11 April, 15:16

wo numbers are randomly selected on a number line numbered from 1 to 9. Match each scenario to its probability. the probability that both numbers are greater than 6 if the same number can be chosen twice the probability that both numbers are less than 7 if the same number can be chosen twice the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice the probability that both numbers are even numbers if the same numbers cannot be chosen twice arrowRight arrowRight arrowRight arrowRight

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  1. 11 April, 15:26
    0
    In all cases, the events are independent. That's why we have to multiply the results.

    Probability that both numbers are greater than 6 if the same number can be chosen twice.

    P = 3 / 9 * 3 / 9 = 1/9 because possible outcomes are the pairs (7,8), (7,9) and (8,9).

    Probability that both numbers are less than 7 if the same number can be chosen twice

    P = 6 / 9 * 6 / 9 = 4/9

    Probability when both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice

    P = 3/9 * 2/8 = 1/12, odd numbers less than 6 are 1, 3 and 5. If the same number cannot be chosen depending on these numbers, we'll end up with 2 in possible outcome for the 2nd pair of the probability.

    Probability that both numbers are even numbers if the same numbers cannot be chosen twice is

    P = 4/9 * 3/9 = 4/27. The same logic is possible in this case, as well
  2. 11 April, 15:26
    0
    the probability that both numbers

    are greater than 6 if the same

    number can be chosen twice = 1/9

    the probability that both numbers

    are less than 7 if the same

    number can be chosen twice = 4/9

    the probability that both numbers

    are odd numbers less than 6 if the

    same numbers cannot be chosen

    twice = 1/12

    the probability that both numbers

    are even numbers if the same

    numbers cannot be chosen twice = 1/6
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