a man deposits 45 into an account the next day he makes 3 deposits of 20 $ each a week later he withdraws 105$

The amount available in account at last is $0

Step-by-step explanation:

Given as:

The withdrawal amount from the account at the end = $105

The first deposit amount = $45

The next three deposit amount = $20 each

I. e The second deposit amount = 3 * $20

Or, The second deposit amount = $60

Let The amount available in account at last = $A

Now, According to question

The amount available in account at last = (first deposit amount + second deposit amount) - withdrawal amount from the account at the end

i. e A = ($45 + $60) - $105

Or, A = $105 - $105

∴ A = $0

So, The amount available in account at last = A = $0

Hence, The amount available in account at last is $0. Answer