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9 November, 23:32

Is (p∨q) ∨ (q→p) a tautology, contradiction, or neither?

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  1. 9 November, 23:42
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    Make a truth table, let A = pVq, B = q->p

    p q A B AVB

    0 0 0 1 1

    0 1 1 0 1

    1 0 1 1 1

    1 1 1 1 1

    Since it is True for every possible state of p and q, then it is a tautology.
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