A lion is running 75 feet per second and is 108 feet behind a wildebeest that is running at 66 feet per second. A lion can only maintain this speed for a very short period. How many seconds will it take lion to catch up to the wildebeest?

Question

Antwan

Mathematics

5 September, 13:29

A lion is running 75 feet per second and is 108 feet behind a wildebeest that is running at 66 feet per second. A lion can only maintain this speed for a very short period. How many seconds will it take lion to catch up to the wildebeest?

+4

Answers (2)

Know the Answer?

Yaretzi Nielsen · Answer 1

12 seconds

Step-by-step explanation:

75 t=66t+108

75t-66t=108

9t=108

t=108/9=12

Deangelo Gonzales · Answer 2

The answer to your question is: 12 seconds

Step-by-step explanation:

Lion v = 75 ft/s

wildebeest = 66 ft/s and is 108 feet behind the lion

t = time = ?

Formula

v = d / t solve for d d = vt

Process

lion d = 75t

wildebeest = d = 108 + 66t

Now

75t = 108 + 66t

solve for t 75t - 66t = 108

9t = 108

t = 12 s