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21 August, 23:17

If f (1) = 4f (1) = 4 and f (n) = f (n-1) ^2+4f (n) = f (n-1) + 4 then find the value of f (3) f (3).

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  1. 21 August, 23:30
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    404

    Step-by-step explanation:

    Use the recursive formula until you get to the term you want.

    f (1) = 4

    f (2) = f (1) ^2 + 4 = 4^2 + 4 = 20

    f (3) = f (2) ^2 + 4 = 20^2 + 4 = 404
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