Fifteen percent of the pigment in paint color A is black. Sixty percent of the pigment in paint color B is black. An unknown amount of paint color B is mixed with 40 ml of paint color A, resulting in a paint that contains 25% black pigment. Which equation can be used to solve for x, the total amount of paint in the mixture of the two colors? 0.15 (40) + 0.6x = 0.25 (40 + x) 0.15 (40) + 0.6 (x - 40) = 0.25 (x) 0.15 (40) + 0.6x = 0.25 (40 - x) 0.15 (40) + 0.6 (x + 40) = 0.25 (x)

Question

Fernando Conrad

Mathematics

7 May, 09:37

Fifteen percent of the pigment in paint color A is black. Sixty percent of the pigment in paint color B is black. An unknown amount of paint color B is mixed with 40 ml of paint color A, resulting in a paint that contains 25% black pigment. Which equation can be used to solve for x, the total amount of paint in the mixture of the two colors? 0.15 (40) + 0.6x = 0.25 (40 + x) 0.15 (40) + 0.6 (x - 40) = 0.25 (x) 0.15 (40) + 0.6x = 0.25 (40 - x) 0.15 (40) + 0.6 (x + 40) = 0.25 (x)

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Amiyah Arellano · Answer 1

Paint colour A - 15% is black

paint colour B - 60% is black

an x volume of B + 40 ml of A

total volume of the mixture = 40 + x

volume of black in 40 ml = 40*0.15

volume of black in x ml = x*0.6

the volume of black in mixture = 0.25 (40 + x)

the total of black in both A and B = (0.15 (40) + 0.6x)

equate the 2 equations above

(0.15 (40) + 0.6x) = 0.25 (40 + x)

1st response is correct