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Karen Chavez
Mathematics
23 April, 08:30
Multiply out 5x (2x-3y)
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Lacey Garner
23 April, 08:47
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You start by distributing the 5x, so that it's 5x (2x) and 5x (3y). That becomes 10x^2 and 15xy. Put it back, and it's 10x^2 - 15xy.
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Alonzo Erickson
23 April, 08:49
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Expand
5x * 2x + 5x * - 3y
Rake out the constants
(5 * 2) x + 5x * - 3y
Simplify 5 * 2 to 10
10x + 5x * - 3y
Use the product rule: x^ax^b = x^a + b
10x^2 + 5x * - 3y
Simplify 5x * - 3y to - 15xy
= 10x^2 - 15xy
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