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16 June, 02:24

How many solution does x^2=4x-5 have

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  1. 16 June, 02:35
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    X^2-4x+5=0

    D = b²-4ac=16-4*5*1=16-20=-4

    so no real solutions, because D<0

    and it is going to be only 2 imaginary solutions
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