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Alena Calhoun
Mathematics
16 June, 02:24
How many solution does x^2=4x-5 have
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Jasmine Sullivan
16 June, 02:35
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X^2-4x+5=0
D = b²-4ac=16-4*5*1=16-20=-4
so no real solutions, because D<0
and it is going to be only 2 imaginary solutions
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