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17 February, 05:07

How do you solve for x in x^2+5x=36

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  1. 17 February, 05:35
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    First we want to set the equation equal to zero by subtracting 36 from each side ...

    x^2 + 5x - 36 = 0

    Now we factor

    (x + 9) (x - 4) = 0

    Now set each expression equal to zero and solve ...

    x + 9 = 0 x - 4 = 0

    x = - 9 x = 4

    Your solution set is

    (-9, 4)
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