State the number of positive and negative real roots

x^7-2x^6-19x+20=0

Question

Hartman

Mathematics

27 July, 03:44

State the number of positive and negative real roots

x^7-2x^6-19x+20=0

+1

Answers (1)

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Doogie · Answer 1

X⁷ - 2x⁶ + 19x + 20 = 0

(x⁶ - 1) (x + 20) = 0

(x³ + 1) (x³ - 1) (x + 20) = 0

x³ + 1 = 0 x³ - 1 = 0 x + 20 = 0

- 1 - 1 + 1 + 1 - 20 - 20

x³ = - 1 x³ = 1 x = - 20

x = - 1 x = 1

State the number of positive and negative real rootsx^7-2x^6-19x+20=0

State the number of positive and negative real roots

x^7-2x^6-19x+20=0