The area of a rectangle is 84 square inches. the length of the rectangle is 2 longer than twice the width. find the width and the perimeter of the triangle

Let l = the lentth of the rectangle and w = the width of the rectangle; where w>0 and l>0;

We have 84 = l x w and l = 2 + w;

84 = (2+w) x w;

We solve the equation: w^2 + 2w - 84 = 0;

We obtain the solution w = 8.21;

The perimeter of the triangle is is 3 x 8.21 = 24.63;