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Find four consecutive multiples of 5 whose sum is 90

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  1. 4 August, 16:07
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    M₅ + (M₅+5) + (M₅+10) + (M₅+15) = 90

    5M₅ + 30=90

    5M₅=90-30

    5M₅=60

    M₅=60:5

    M₅=12

    M₅+5=12+5=17

    M₅+10=12+10=22

    M₅+15=12+15=27
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