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23 January, 20:29

Obtain the derivative of/ / (bx^n//), where/ / (b//) is a constant and / / (n//) is a positive integer

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  1. 23 January, 20:49
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    bn[x^ (n-1) ]

    Step-by-step explanation:

    d (b*x^n) / dx

    = b * n * x^ (n - 1)

    = bn[x^ (n-1) ]
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