Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 4, and b = 10.

Question

Erick

Mathematics

8 November, 14:29

Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 4, and b = 10.

+5

Answers (2)

Know the Answer?

Lam · Answer 1

Answer: The answer is zero.

Areli Roach · Answer 2

None

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines - Ambiguous Case', we have,

If a < b*sinA, then no triangle is possible.

If a = b*sinA, only one triangle is possible

If a > b*sinA, two triangles are possible.

So, we have,

b*sinA = 10 * sin30 = 10 * 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.