2 planes left a airport at noon 1 flew east and the other flew west as twice the speed after 3 hours the planes were 2700 miles apart. How fast was each plane flying?

X=speed of the first plane. (east)

2x=speed of the second plane (west).

we can suggest this equation:

3 (x+2x) = 2700

3 (3x) = 2700

9x=2700

x=2700/9

x=300

speed of the first plane=300 miles/h

speed of the second plane=2x=2 (300 miles/h) = 600 miles/h.

Answer: the speed of the first plane was 300 miles/h, and the speed of the second plane was 600 miles/h.

Speed = distance : time

?=2700:3

?=900 miles per hour