A car approaches a stop sign going 5 m/s before it comes to a stop. If it does this in 4 seconds, what was

its acceleration?

Acceleration = - 1.25 m/s²

Step-by-step explanation:

Given dа ta:

initial velocity = 5 m/s

Final velocity = 0 m/s since the car stopped

change in time = 4 seconds

Acceleration = change in velocity/change in time

Acceleration = (Final velocity - Initial velocity) / time

Acceleration = (0-5) / 4

Acceleration = - 5/4

Acceleration = - 1.25 m/s²

The acceleration in negative since the car was reducing speed to stop, it can also called deceleration.