Why is 3tan^2θ - 1 = 0 equal to - pi/6 and pi over 6?

My first steps were to isolate the θ and I got + and - sqrt 3 / 3

Looking on my unit circle I got four answers (pi/6), (5pi/6),7pi/6), and (11pi/6)

however my textbook says that the answers are - pi/6 and pi over 6 ... why?

Question

25 November, 00:59

+4

Answers (1)

Know the Answer?

Jax Andrews · Answer 1

Your answers are correct. Just carefully read the question and see what interval do they suggest for the solutions to find in?

Why is 3tan^2θ - 1 = 0 equal to - pi/6 and pi over 6?My first steps were to isolate the θ and I got + and - sqrt 3 / 3Looking on my unit circle I got four answers (pi/6), (5pi/6),7pi/6), and (11pi/6)however my textbook says that the answers are - pi/6 and pi over 6 ... why?