Three data entry specialists enter requisitions into a computer. Specialist 1 processes 30 percent of the requisitions, specialist 2 processes 45 percent, and specialist 3 processes 25 percent. The proportions of incorrectly entered requisitions by data entry specialists 1, 2, and 3 are 0.03, 0.05, and 0.02, respectively. Suppose that a random requisition is found to have been incorrectly entered. What is the probability that it was processed by data entry specialist 1

Question

Nancy Martinez

Mathematics

4 November, 12:56

Three data entry specialists enter requisitions into a computer. Specialist 1 processes 30 percent of the requisitions, specialist 2 processes 45 percent, and specialist 3 processes 25 percent. The proportions of incorrectly entered requisitions by data entry specialists 1, 2, and 3 are 0.03, 0.05, and 0.02, respectively. Suppose that a random requisition is found to have been incorrectly entered. What is the probability that it was processed by data entry specialist 1

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Zion Bond · Answer 1

Answer: = 0.2465

Step-by-step explanation:

Firstly the probability that a random requisition is entered by data entry specialist 1 equals 0.3, by data

entry specialist 2 equals 0.45, by data entry specialist 3 equals 0.25.

probability (p1) =

(0.3 * 0.03

) / (0.3 * 0.03 + 0.45 * 0.05 + 0.25 * 0.02) = 0.2465