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2 December, 12:36

Solve the system by the substitution method. Show your work.

2y - x = 5

x^2 + y^2 - 25 = 0

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  1. 2 December, 12:55
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    2y - x = 5

    x^2 + y^2 - 25 = 0

    x = 2y - 5

    (2y-5) ^2 + y^2 - 25 = 0

    (2y-5) (2y-5) + y^2 - 25 = 0

    4y^2 - 20y + 25 + y^2 - 25 = 0

    5y^2 - 20y = 0

    y = 0, y = 4

    x = 2y - 5, when y = 0

    x = - 5

    x = 2y - 5, when y = 4

    x = 8 - 5

    x = 3
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