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6 January, 08:53

The larger of two numbers is twelve more than twice the smaller number. The sum of the numbers is fifty one. Find each number

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Answers (2)
  1. 6 January, 09:13
    0
    Answer: 13 and 38

    Step-by-step explanation:

    Let the smaller number be y.

    Larger number will be 2y+12

    Since the sum of the numbers is 51,

    y + 2y + 12 = 51

    3y + 12 = 51

    3y = 51 - 12

    3y = 39

    y = 39/3

    y = 13

    The smaller number is 13

    The bigger number will be 2y + 12 = 2 (13) + 12 = 26 + 12 = 38
  2. 6 January, 09:14
    0
    13 and 38

    Step-by-step explanation:

    So we know that one number is 2 times the smaller number plus 12. We can use the variable x for the smaller number and the bigger number will be 2x + 12. Now we need to put the numbers into an equation.

    2x + 12 + x = 51

    To isolate x, we have to subtract 12 from the left side of the equation.

    2x + x = 39

    Now we add the x's together.

    3x = 39

    Now we have to divide by 3.

    x = 13

    But we're not done yet, although we know the smaller number is 13 we have to plug x into the larger number. So because it is 2x the amount, we multiply 13 to get 26 and then add another 12 to get 38.
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