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18 May, 18:45

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distance d away. The bear is 30 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely.

What is the maximum possible value for d?

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  1. 18 May, 18:48
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    V = d/t

    t = d/v

    v (Bear) = 6.0 m/s, v (Tourist) = 4.2 m/s

    (30 m + d) / 6 m/s = d / 4.2 m/s

    4.2 (30 + d) = 6 d

    126 + 4.2 d = 6 d

    6 d - 4.2 d = 126

    1.8 d = 126

    d = 126 : 1.8 = 70 m

    Answer:

    The maximum possible value for d is 70 m.
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