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9 May, 07:05

What values for theta (0 < = theta < = 2pi) satisfy the equation?

2 sin theta cos theta + sqrt 3 cos theta = 0

a. pi/2, 4pi/3, 3pi/2, 5pi/3

b. pi/2, 3pi/4, 3pi/2, 5pi/3

c. pi/2, 3pi/4, 3pi/2, 5pi/4

d. pi/2, pi/4, 3pi/2, 5pi/3

+4
Answers (1)
  1. 9 May, 07:11
    0
    2 sin t cos t + √3 cos t = 0

    cos t (2 sin t + √3) = 0

    Therefore:

    cos t = 0, t 1 = π/2, t 2 = 3 π/2

    or:

    2 sin t + √3 = 0

    2 sin t = - √3

    sin t = - √3 / 2

    t 3 = 4 π/3, t 4 = 5 π/3

    Answer:

    a) π/2, 4π/3, 3π/2. 5π/3.
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