Ask Question
6 October, 02:57

At a fabrication plant, 9 of the employees each earn $10,000 per quarter and 1 employee earns $70,000 per quarter.

Part A: Find the median and mean of the salary per quarter.

Part B: The industry employee average salary for fabrication plants is $13,000 per quarter. Mr. Gomez is trying to recruit people to work for the plant. How might he advertise the position using the mean salary?

Part C: Evaluate the advertisement in Part B. Do you agree with the claim made in the advertisement? Explain.

Show work for all the problems.

+3
Answers (2)
  1. 6 October, 03:00
    0
    A

    La media es 10,000

    El promedio es 16,000

    B

    Mr Gomez podría poner en el anuncio que el promedio del sueldo de los trabajadores de su fábrica es 16,000, que es 3,000 más que lo que gana un trabajador promedio.

    C

    No estoy de acuerdo, por que en realidad el salario del 90% de los trabajadores de esa fábrica es 10,000, lo que está 3,000 por debajo de el salario promedio de otras fábricas.
  2. 6 October, 03:14
    0
    A.

    $10,000

    $10,000

    $10,000

    $10,000

    $10,000

    $10,000

    $10,000

    $10,000

    $10,000

    $70,000

    $160,000 / 10 = $16,000 Mean

    Median = ($10,000 * 2 / 2) = $10,000

    B. He can advertise the position by emphasizing that a high initial compensation will be offered since $13,000 is greater than the previous salary offered to employees.

    C. Yes, I agree because the previous salary offered was just $10,000 but now it is being increased to $13,000.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At a fabrication plant, 9 of the employees each earn $10,000 per quarter and 1 employee earns $70,000 per quarter. Part A: Find the median ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers