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17 May, 09:22

A group of 10 people need to form a line. The line will consist of exactly 8 of the people. Person X and Person Y have to be either fifth or sixth in line. How many different orders are possible?

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  1. 17 May, 09:47
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    Answer: N = 40,320

    Step-by-step explanation:

    To arrange 10 people to a line of 8 people.

    The number of ways is n = 10P8.

    But since the condition given states that 2 people must stay in two particular slots.

    The number of possible arrangements becomes;

    N = number of ways of arranging the remaining people * number of ways of arranging the other 2.

    N = 8P6 * 2P2

    N = 8!/2! * 2!

    N = 20,160 * 2

    N = 40,320 ways
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