Ask Question
6 December, 10:31

Consider the function g (x) = 5x2-18x+35. find the area under the curve g (x) from x = 0 to x = 13 and then subtract from it the area under the same curve g (x) from x = 0 to x=1. what is the difference?

+5
Answers (1)
  1. 6 December, 10:43
    0
    We integrate the given equation such that,

    integral of g (x) = (5/3) x³ - 9x² + 35x

    Substituting,

    x = 13

    integral of g (x) = (5/3) (13³) - 9 (13) ² + 35 (13)

    = 2595.67

    and, x = 0

    integral of g (x) = 0

    The area is 2595.67 - 0 = 2595.67

    For the second part,

    x = 1

    integral of g (x) = (5/3) (1) ³ - 9 (1) ² + 35 (1)

    = 27.67

    Area under the curve between x = 0 and x = 1 is 27.67

    The difference between the two areas is,

    2595.67 - 27.67 = 2568.0

    Answer: 2568.0 units squared
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Consider the function g (x) = 5x2-18x+35. find the area under the curve g (x) from x = 0 to x = 13 and then subtract from it the area under ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers