We know the following about the numbers a, b and c:

(a + b) ^2 = 9,

(b + c) ^2 = 25, and

(a + c) ^2 = 81.

If a + b + c ≥ 1, determine the number of possible values for a + b + c.

Question

Beau Carroll

Mathematics

14 July, 08:23

We know the following about the numbers a, b and c:

(a + b) ^2 = 9,

(b + c) ^2 = 25, and

(a + c) ^2 = 81.

If a + b + c ≥ 1, determine the number of possible values for a + b + c.

+1

Answers (1)

Know the Answer?

Elena Zuniga · Answer 1

Step-by-step explanation:

(a + b) ² = 9

(b + c) ² = 25

(a + c) ² = 81

Taking the square root:

a + b = ±3

b + c = ±5

a + c = ±9

By adding these three equations together and dividing both sides by 2, we get the value of a + b + c.

Possible combinations for a + b + c such that the sum is greater than or equal to 1 are:

a + b + c = (-3 + 5 + 9) / 2 = 11/2

a + b + c = (3 - 5 + 9) / 2 = 7/2

a + b + c = (3 + 5 + 9) / 2 = 17/2

We know the following about the numbers a, b and c:(a + b) ^2 = 9,(b + c) ^2 = 25, and(a + c) ^2 = 81.If a + b + c ≥ 1, determine the number of possible values for a + b + c.

We know the following about the numbers a, b and c:

(a + b) ^2 = 9,

(b + c) ^2 = 25, and

(a + c) ^2 = 81.

If a + b + c ≥ 1, determine the number of possible values for a + b + c.