A square is changed into a new rectangle by increasing its width by 2 inches and decreasing its length by 2

inches. If the original square had a single length of 8 inches, find it's area and the area of the new rectangle. How many square inches larger is the square's area?

Answer: The area of the square is 64 square inches and the area of the new rectangle is 60 square inches. The square's area is 4 inches larger than the rectangle.

Step-by-step explanation: If a side length of the square measures 8 inches, then its area can be calculated as follows;

Area = L x W

The length and the width both measure 8 inches (all sides of a square are equal in length).

Area = 8 x 8

Area = 64

Also, the the new rectangle is formed by increasing the width of the square by 2 inches (that is 8 + 2 = 10), and decreasing the length by 2 inches (that is 8 - 2 = 6). The area of the new rectangle is calculated as follows;

Area = L x W

Area = 10 x 6

Area = 60

Therefore the area of the square is 64 square inches and the area of the rectangle is 60 square inches. The area of the square is 4 inches larger than that of the rectangle.