What is the area of a parallelogram if the coordinates of its vertices are (0, - 2), (3, 2), (8, 2), and (5, - 2) ?

The area of the parallelogram is 20 unit²

Step-by-step explanation:

We have that the area of a parallelogram = Base length, l * Height, h

The length of the base, l = √ ((5 - 0) ² + (-2 - (-2)) ²) = 5

Given that the base of the parallelogram is parallel with to the x-axis, we have that the height is the difference between the a higher and a lower y-coordinate as follows;

h = y₃ - y₁ = 2 - (-2) = 2 + 2 = 4

Therefore, the area of the parallelogram, A = l * h = 4 * 5 = 20 unit².