With a fair die, the probability of rolling any number 1 through 6 is the same.

If P (1) represents the probability of rolling a 1, P (2) the probability of rolling a 2, and so forth, what is the value of: P (1) + P (2) + P (3) + P (4) + P (5) + P (6)

Question

Yadira Charles

Mathematics

18 April, 23:31

With a fair die, the probability of rolling any number 1 through 6 is the same.

If P (1) represents the probability of rolling a 1, P (2) the probability of rolling a 2, and so forth, what is the value of: P (1) + P (2) + P (3) + P (4) + P (5) + P (6)

+4

Answers (2)

Know the Answer?

Broderick Ross · Answer 1

P (any number from 1 to 6) = 1/6

so the sum of P (1) + P (2) etc is 6*1/6 = 1

Santos Jones · Answer 2

The probability of all possible outcomes is always 1, meaning 100%.

In this case the probability of rolling a 1,2,3,4,5, or 6 is:

1/6+1/6+1/6+1/6+1/6+1/6

6 (1/6)

6/6

1

With a fair die, the probability of rolling any number 1 through 6 is the same.If P (1) represents the probability of rolling a 1, P (2) the probability of rolling a 2, and so forth, what is the value of: P (1) + P (2) + P (3) + P (4) + P (5) + P (6)

With a fair die, the probability of rolling any number 1 through 6 is the same.

If P (1) represents the probability of rolling a 1, P (2) the probability of rolling a 2, and so forth, what is the value of: P (1) + P (2) + P (3) + P (4) + P (5) + P (6)