F (x) = 2+3cosπ10 (x-3) Find f (47).

Question

Cecelia Gates

Mathematics

11 June, 13:55

F (x) = 2+3cosπ10 (x-3) Find f (47).

+1

Answers (2)

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Natalya Huff · Answer 1

F (x) = 2 + 3cos (10π (x - 3))

f (47) = 2 + 3cos (10 (3.14) (47 - 3))

f (47) = 2 + 3cos (31.4 (45))

f (47) = 2 + 3cos (1413)

f (47) = 2 + 3 (0.891006524)

f (47) = 2 + 2.673019573

f (47) = 4.673019573

is the right awnser

Brice · Answer 2

f (x) = 2 + 3cos (10π (x - 3))

f (47) = 2 + 3cos (10 (3.14) (47 - 3))

f (47) = 2 + 3cos (31.4 (45))

f (47) = 2 + 3cos (1413)

f (47) = 2 + 3 (0.891006524)

f (47) = 2 + 2.673019573

f (47) = 4.673019573