Two buses leave towns 339 miles apart at the same time and travel toward each other. One bus travels 13 mi/h slower than the other. If they meet in 3 hours, what is the rate of each bus?

Step-by-step explanation:

Let x m/h be the speed of first bus.

Then speed of second bus=x-13 m/h

fist covers covers distance=3x

second covers the distance=3 (x-13) = 3x-39

again 3x + (3x-39) = 339

6x=339+39=378

x=378/6=63

so speed of first bus=63 m/h

speed of second bus=63-13=50 m/h