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11 July, 05:11

Prove that if the real-valued function f is strictly increasing, then f is oneto-one.

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  1. 11 July, 05:30
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    See proof below

    Step-by-step explanation:

    Let x, y be arbitrary real numbers. We want to prove that if x≠y then f (x) ≠f (y) (this is the definition of 1-1).

    If x≠y, we can assume, without loss of generality that x
    Because f is strictly increasing, x
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