If the equation was A=d (1.005) ^12t models an investment A after t years with an initial deposit d, what would the value of the investment be if he had deposited $1000?

Step-by-step explanation:

A=d (1.005) ^12t

where d=1000

so the equation will be:

A=1000 (1.005) ^12t

but if the time given, let say t=4

A=1000 (1.005) ^12t

subtitute t into the equation

A=1000 (1.005) ^ (12*4)

A=1000 (1.005) ^36

A=1000 (1.197)

A=1197

so if he deposit $1000 after 4 years the investment will be around $1197