On a certain hot summer's day, 611 people used the public swimming pool. The daily prices are $ 1.75 for children and $ 2.00 for adults. The receipts for admission totaled $ 1143.75. How many children and how many adults swam at the public pool that day?

298 adults and 313 children

Step-by-step explanation:

In this case we can solve it using a 2x2 system of equations, like this:

let x: children's tickets

let y: adult's tickets

So:

1.75 * x + 2 * y = 1143.75

x + y = 611 = > x = 611 - y

Replacing, we are left with that:

1.75 * (611 - y) + 2 * y = 1143.75

1069.25 - 1.75 * y + 2 * y = 1143.75

- 1.75 * y + 2 * y = 1143.75 - 1069.25

0.25 * y = 74.5

y = 74.5 / 0.25

y = 298

Now to calculate x:

x = 611-298

x = 313

It means that there were 298 adults and 313 children