The heights of fully grown English oak (also known as Brown oak) trees are normally distributed with a mean of 95 feet and a standard deviation of 10 feet. What proportion of fully grown English oak trees are taller than 110 feet?

Question

Kaufman

Mathematics

2 May, 20:07

The heights of fully grown English oak (also known as Brown oak) trees are normally distributed with a mean of 95 feet and a standard deviation of 10 feet. What proportion of fully grown English oak trees are taller than 110 feet?

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Answers (1)

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Kaylie · Answer 1

Standard normal distribution formula is

z = (x - μ) / σ

μ = 95

σ = 10

z = (110-95) / 10

= 1.5

the probability z>1.5 using the standardization table = 0.0668

P (z > 1.5) = 0.0668