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7 January, 10:28

Write the virtud for a parabola that satisfies the condition given. Then write the equation in the form y=ax^2+bc+c. Vertex (3,1) and a=3 write the equation in the form y=ax^2+bx+c

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  1. 7 January, 10:40
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    y = 3 (x - 3) ^2 + 1 y = 3x^2 - 18x + 28

    Step-by-step explanation:

    For vertex (h, k) and vertical scale factor "a", the vertex form of the equation of a parabola is ...

    y = a (x - h) ^2 + k

    For (h, k) = (3, 1) and a = 3, the equation in vertex form is ...

    y = 3 (x - 3) ^2 + 1

    __

    Expanding this gives the equation in standard form.

    y = 3 (x^2 - 6x + 9) + 1

    y = 3x^2 - 18x + 28
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