Solving linear systems of substitution

Example: 2x+2y=8 and 3y+2x=6

Okay so u first want to put on of the equations into a y = form. So let's use 3y+2x=6. Subtract 2x from both sides. 3y=6-2x divide by 3. Y = 6-2/3x or y = - 2/3x + 6. Now just plug this new equation in for Y since "y=" into the other equation.

2x + 2 (-2/3x + 6) = 8.

Then you would distribute the 2 into the parenthesis and simplify to solve for x.

After you solve for x, plug x into one of the original equations to find y.