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Amelie Mora
Mathematics
1 April, 21:37
Find f (-2) for the function:
f (x) = 3x^2-1, x<1
x+2, x> 1
+4
Answers (
1
)
Stokes
1 April, 21:50
0
F (x) = 3x² - 1
f (-2) = 3 (-2) ² - 1
f (-2) = 3 (4) - 1
f (-2) = 12 - 1
f (-2) = 11
f (x) = x < 1
f (-2) = - 2 < 1
f (x) = x + 2
f (-2) = - 2 + 2
f (-2) = 0
f (x) = x > 1
f (-2) = - 2 > 1
f (-2) = - 2 < 1
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