2. Mary deposited $8000 in an account that pays 6% annual interest for 5 years. Using A=p (1+r) ^t, what is the balance at the end of the 5 years?

Question 2 options:

a. 10706

b. 0.006

c. 134456000

d. 83886

3. Mary deposited $8000 in an account that pays 6% annual interest compounded quarterly for 5 years. What is the balance at the end of the 5 years? Use A = p (1 + rn) n*t

a. 10706

b. 10775

c. 12806

d. 8652

4. A $15,000 car depreciates at 20% each year. If you were to write an exponential model in the form, which value represents B in the function? (which is the growth factor)

a. 15,000

b. 0.2

c. 0.8

d. 0.02

Question

Douglas Sandoval

Mathematics

12 April, 04:33

2. Mary deposited $8000 in an account that pays 6% annual interest for 5 years. Using A=p (1+r) ^t, what is the balance at the end of the 5 years?

Question 2 options:

a. 10706

b. 0.006

c. 134456000

d. 83886

3. Mary deposited $8000 in an account that pays 6% annual interest compounded quarterly for 5 years. What is the balance at the end of the 5 years? Use A = p (1 + rn) n*t

a. 10706

b. 10775

c. 12806

d. 8652

4. A $15,000 car depreciates at 20% each year. If you were to write an exponential model in the form, which value represents B in the function? (which is the growth factor)

a. 15,000

b. 0.2

c. 0.8

d. 0.02

+2

Answers (1)

Know the Answer?

Cade May · Answer 1

Hi there

1)

A=8,000 * (1+0.06) ^ (5)

A=10,705.8 round your answer to get

A=10706

2)

A=8,000 * (1+0.06:4) ^ (4*5)

A=10,774.8 round to get

A=10775

3) with depreciation the formula is

V (t) = Vb^t

Where b = (1-r) (r rate of depreciation)

B=1-0.2=0.8

Good luck!