At the start of his diet kerrin weighed 13 stone 9 pounds. three months later he weighed 12 stone 7 pounds. there are 14 pounds in a stone. calculate the reduction in kerrin's weight as a percentage of his initial weight

These are all done in exactly the same way (1) Find the actual change here 14 st 12lb - 13 st 10 lb; 4 lb to take you up to 14 st. then another 12 llb; i. e. actual loss = 16 lb; (2) the original weight was

14 x 14 + 12 lb = 208 lb so as a fraction of the original weight, loss = 16/208;; to convert any fraction to a %, multiply the fraction by 100% - in this case, 16/208 x 100% = 1/13 x 100 % = 100/13% = 7.692 ... % = 7.7% correct to 1 d. p. That was assuming you are not using a calculator. If you are, do 16/208, % and that should give you the answer. unfortunately some calculators have some very strange "logic" built into them ... If that doesn't give you the answer 7.692 ..., take it to your teacher, he/she will tellyou within seconds just how your calculator works.

As a general rule, do the following steps (find the actual change (2) make the fraction Actual change/Original value (3) either x100 as above or by calculator, press "%" and that should give you the answer

I did this a little differently. I converted the stones to pounds from the beginning. 13 st 9 lb. = 191 lbs. (13x14+9); 12 st 7 lbs. = 175 lbs. (12x14+7) percent change is : amount of change / original (191-175) / (191) = 16/191 = 0.084 or 8.4%